php+jquery+ajax+json的一个简单实例

#   php+jquery+ajax+json的一个简单实例



<html>
<head>
<meta http-equiv="content-type" content="text/html;charset=utf-8" />
<script type="text/javascript" src="jquery-1.8.2.min.js"></script>
<script type="text/javascript">
 $(function(){
  $("#send").click(function(){
   var cont = $("input").serialize();
   $.ajax({
    url:'ab.php',
    type:'post',
    dataType:'json',
    data:cont,
    success:function(data){
     var str = data.username + data.age + data.job;
     $("#result").html(str);
    }
   });
  });  
 });
</script>
</head>
<body>
 <div id="result">一会看显示结果</div>
 <form id="my" action="" method="post">
  <p><span>姓名:</span><input type="text" name="username" /></p>
  <p><span>年龄:</span><input type="text" name="age" /></p>
  <p><span>工作:</span><input type="text" name="job" /></p>
 </form>
 <button id="send">提交</button>
</body>
</html>
-------------------------------------------------------------------------------------------------------------
<?php
header("Content-type:text/html;charset=utf-8");
$username = $_POST['username'];
$age = $_POST['age'];
$job = $_POST['job'];
$json_arr = array("username"=>$username,"age"=>$age,"job"=>$job);
$json_obj = json_encode($json_arr);
echo $json_obj;
?>


# xiaoxiao [ 2018-02-26 ]

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